tag:blogger.com,1999:blog-11438609.post2853324796553844633..comments2023-10-15T11:41:51.983+01:00Comments on Ex-Ku-Malha: Jantar de Natal 2014parreirexhttp://www.blogger.com/profile/03340253214797908391noreply@blogger.comBlogger21125tag:blogger.com,1999:blog-11438609.post-18446351898024136232014-12-19T16:05:11.655+00:002014-12-19T16:05:11.655+00:00olá Célia!!
Podes enviar-me o teu nº de telefone: ...olá Célia!!<br />Podes enviar-me o teu nº de telefone: patriciamarqs@gmail.com. Isto porque vou ter de cancelar a minha ida em principio... beijinhos, pituchaP.M.https://www.blogger.com/profile/07076130358115142612noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-71055010592905625812014-12-19T10:45:44.499+00:002014-12-19T10:45:44.499+00:00Uau, organizaste isto tudo?
Parabéns Célia! ;)
At...Uau, organizaste isto tudo? <br />Parabéns Célia! ;)<br />Até amanhã!fAipeshttps://www.blogger.com/profile/12374573485684816865noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-49564677724488303782014-12-18T23:44:08.238+00:002014-12-18T23:44:08.238+00:00programa para sábado, dia 20, na baixa de coimbra
...programa para sábado, dia 20, na baixa de coimbra<br /><br /><i><br />Actuação dos Dixie Gringos<br />Hora: 10h30, 13h00, 14h30 e 17h00<br />Animação musical itinerante pelas ruas<br /><br />Animação Pai Natal<br />Hora: 11h00 às 13h00<br />Animação com Pai Natal, itinerante pelas ruas<br /><br />Leva-me<br />Hora: 15h00 às 18h00<br />Local: estabelecimentos comerciais da Baixa de Coimbra Projecto em dois momentos distintos:<br />- o primeiro constitui-se por um conjunto de animações nas montras de lojas da Baixa que vão albergar, nas suas vitrinas, autores e figurinos alheios ao hábito de cada uma delas;<br />- o segundo pelo encerramento com uma festa com a presença de todos os performers, público e transeuntes contando com a animação musical com Dj's.<br />Entrada Livre<br /><br />Festa de Encerramento<br />Hora: 18h às 20h<br />Local: Centro de Artes Visuais (CAV)<br />Entrada Livre<br /></i>chica de moebiushttps://www.blogger.com/profile/09496910420914050534noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-42043180355881503672014-12-18T18:09:21.235+00:002014-12-18T18:09:21.235+00:00está tudo confirmado!
podem ir aparecendo a partir...está tudo confirmado!<br />podem ir aparecendo a partir do 12:00.<br />beijitos.chica de moebiushttps://www.blogger.com/profile/09496910420914050534noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-63703624950171303982014-12-17T22:20:30.888+00:002014-12-17T22:20:30.888+00:00@ ger,
em princípio haverá por aqui pessoal até p...@ ger,<br /><br />em princípio haverá por aqui pessoal até pelo menos às 3 da manhã.parreirexhttps://www.blogger.com/profile/03340253214797908391noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-71234493236472423102014-12-17T15:06:51.064+00:002014-12-17T15:06:51.064+00:00Olá pessoal lindo!!! de leiria vamos 3! beijooooo ...Olá pessoal lindo!!! de leiria vamos 3! beijooooo pituchaP.M.https://www.blogger.com/profile/07076130358115142612noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-65906474154892674912014-12-17T06:20:42.118+00:002014-12-17T06:20:42.118+00:00O meu voo chega ao Porto nö sabado antes das 15.
...O meu voo chega ao Porto nö sabado antes das 15.<br /><br />Se houver pessoal em Coimbra a hora mais avancada posso ir ai ter.<br /><br />--- Ger ---Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-11438609.post-52495788677064897382014-12-16T22:17:38.801+00:002014-12-16T22:17:38.801+00:00Presente!Presente!Tânia Bragahttps://www.blogger.com/profile/15181014453227823933noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-10336530066580021312014-12-13T15:16:19.001+00:002014-12-13T15:16:19.001+00:00Presentes!! (Reserva para 3)Presentes!! (Reserva para 3)Césarhttps://www.blogger.com/profile/07777030289610462377noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-69296355522661307212014-12-12T11:14:50.805+00:002014-12-12T11:14:50.805+00:00Contem comigo (1).Contem comigo (1).Limahttps://www.blogger.com/profile/05761705393787630862noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-74222997800429375762014-12-10T17:37:52.224+00:002014-12-10T17:37:52.224+00:00Eu e a Ana estamos lá.... :)Eu e a Ana estamos lá.... :)Nunexnoreply@blogger.comtag:blogger.com,1999:blog-11438609.post-50683789018339733812014-12-09T22:56:30.334+00:002014-12-09T22:56:30.334+00:00Ok, estou lá. Por mim podemos repetir a dose!Ok, estou lá. Por mim podemos repetir a dose!Moreirahttps://www.blogger.com/profile/04224971241878058510noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-42750919046082637172014-12-09T22:08:22.667+00:002014-12-09T22:08:22.667+00:00mudança de planos!
a semana passada já não foi pos...mudança de planos!<br />a semana passada já não foi possível marcar no nacional. reservei lugar n'o pátio (onde jantámos na última mega saída: jantar, cav, quebra, caldeiras, base tango, states e pequeno almoço no panorama) para <b>20</b> adultos e <b>5</b> crianças.<br />assim, comecem a confirmar presenças...chica de moebiushttps://www.blogger.com/profile/09496910420914050534noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-43922297286053777242014-12-06T08:14:52.671+00:002014-12-06T08:14:52.671+00:00let N=2K
(1) If K is a prime number then K+K=N
...let N=2K<br /><br /> (1) If K is a prime number then K+K=N<br /><br /> (2) If K is not a prime number<br /><br /> we have that Q1=K has prime factors (set I)<br /><br /> Let us define Q2 in the following way:<br /><br /> p_i lowest prime number not belonging to I.<br /><br /> (2.1) If p_i>K-2 then K-1 should be a prime number, since it bdoes not belong<br /> to I (k is divisible by each prime factor of K, but they doe not dive K-1).<br /><br /> And K+1 is also a prime number, since each prime factor of K and K-1 does not<br /> divide K+1 (K>2, K=2 would be case (1)):<br /><br /> (2.2)<br /><br /> If p_i K-2<br /><br /> p_1,..., p_i is the set J<br /><br /><br /><br /> Q1+Q2 is not divisible by prime number P belonging to I or J, because a prime<br /> number belonging to I is not divisible to Q2, and a prime number belonging to J<br /> is not divisible to Q1, so it is not divisible to Q1+Q2 and Q1-Q2.<br /><br /> so the product(p1,...,pi,P)>K-2<br /><br /><br /><br /> Q1-Q2=aP, where P is the smallest prime factor<br /><br /> We have P>p_i for p_i belonging to J and<br /><br /> aP<=K, so a<=K,<br /><br /> let P1 be the smallest prime factor of a, then a should belong to J, what is a<br /> contradiction, so P=Q1-Q2 is a prime number.<br /><br /> for Q1+Q2,<br /><br />let Q1+Q2=a2*P2, with P2 smallest prime factor.<br /><br />a1*P1+(Q1+Q2)=2*K<br />(Q1+Q2)=2*K-a1*P1<br /><br />we have that (Q1+Q2) does no belong to I and J,<br />so we have (Q1+Q2)=a2*P2, with P2 not belonging to I and J, and different from P1.<br /><br />(Q1+Q2)-(Q1-Q2)=2*Q1=N<br />a2*P2-a1*P1=N<br /><br />P1 and P2 are not divisible by each prime number of I and J. But N is divisible by each prime number of I and 2, so P1 and P2 are prime number and not divisible by each other, because in that case N would be divisible by them.<br /><br />a1*P1+a1*P1<br /><br />Q2=a2*P2<K-1<br />that is a2 has a prime factor belonging to J, what is a contradiction.<br /><br /><br /> So (Q1+Q2)+(Q1-Q2)=N<br /><br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-11438609.post-80355271570549520672014-12-06T07:38:34.751+00:002014-12-06T07:38:34.751+00:00Correccao da prova, (Paulo Goncalves, GER)
let N...Correccao da prova, (Paulo Goncalves, GER)<br /><br /><br />let N=2K<br /> (1) If K is a prime number then K+K=N<br /> (2) If K is not a prime number<br /> we have that Q1=K has prime factors (set I)<br /> Let us define Q2 in the following way:<br /> p_i lowest prime number not belonging to I.<br /> (2.1) If p_i>K-2 then K-1 should be a prime number, since it bdoes not belong to I (k is divisible by each prime factor of K, but they doe not dive K-1).<br /> And K+1 is also a prime number, since each prime factor of K and K-1 does not divide K+1 (K>2, K=2 would be case (1)):<br /> (2.2)<br /> If p_i K-2<br /> p_1,..., p_i is the set J<br /><br />Q1+Q2 is not divisible by prime number P belonging to I or J, because a prime number belonging to I is not divisible to Q2, and a prime number belonging to J is not divisible to Q1, so it is not divisible to Q1+Q2 and Q1-Q2.<br /> so the product(p1,...,pi,P)>K-2<br /><br />Q1-Q2=aP, where P is the smallest prime factor<br /> We have P>p_i for p_i belonging to J and<br /> aP<=K, so a<=K,<br /> let P1 be the smallest prime factor of a, then a should belong to J, what is a contradiction, so P=Q1-Q2,<br /> for PQ=Q1+Q2,<br /> K<Q1+Q2<2*K-1<br /> 0<Q2<K-1, sibnce Q1=K,<br /><br />Q2=a2*P2, where P2 is the smallest prime factor, and does not belong to I and J for the same reason as above.<br /> Then<br /> a2*P2<K-1<br /> Let P3 be the smallest prime factor of a2 then<br /> P3<=p_1*...*p_i, what is a contradiction, because then P3 should belong J.<br /><br />So (Q1+Q2)+(Q1-Q2)=NAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-11438609.post-31362957818148042322014-12-05T14:23:19.410+00:002014-12-05T14:23:19.410+00:00espalhem por favor por todo o mundo.
Paulo Gonca...espalhem por favor por todo o mundo.<br /><br /><br />Paulo GoncalvesAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-11438609.post-91713510844384076372014-12-05T14:22:04.966+00:002014-12-05T14:22:04.966+00:00Goldbach
let N=2K
we have that Q1=K has prime fac...Goldbach<br /><br />let N=2K<br />we have that Q1=K has prime factors (set I)<br />Let us be Q2 be in the following way.<br />pi lowest prime number not belonging to I.<br />If pi K<br />p1,..., pi is the set J<br /><br />Q1+Q2 is not divisible by prime number P belonging to I or J,<br />so product(p1,...,pi,P)>K<br /><br />Q1=aP, where P is the smallest prime factor<br />We have P<pi, pi beopnging to J<br />aP<=K, so a<=K,<br />let P1 be the smallest prime factor of a, then a should belong to J, what is a contradiction, so P=Q1+Q2,<br />analogeu for Q1-Q2.<br /><br />So (Q1+Q2)+(Q1-Q2)=N<br /><br /><br /><br />Paulo Goncalves, GER (de Munique)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-11438609.post-63253264745988320112014-12-05T09:37:38.081+00:002014-12-05T09:37:38.081+00:00parece-me bem... em principio cá de casa somos 3 (...parece-me bem... em principio cá de casa somos 3 (sara, mãe da sara e pai da sara)ursãohttps://www.blogger.com/profile/18368309613255415819noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-53068869845438662982014-12-03T20:42:49.189+00:002014-12-03T20:42:49.189+00:00Célia
Falei ontem com o Pedro sobre este assunto,...Célia<br /><br />Falei ontem com o Pedro sobre este assunto, e ele falou da sala do rés-do-chão por ser mais seguro para os miúdos. Tenta saber quantos lugares aquilo leva (deve chegar para nós de certeza... aposto em 20 px + ou -).Moreirahttps://www.blogger.com/profile/04224971241878058510noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-23824641289379738402014-12-02T21:49:00.186+00:002014-12-02T21:49:00.186+00:00novo local proposto: nacional (fica na baixa atrás...novo local proposto: <a href="http://www.restaurantenacional.pt/" rel="nofollow">nacional</a> (fica na baixa atrás do arnado, na rua mário pais)<br /><br />hora proposta: 12:00 ou 12:30 (para que as crianças possam almoçar connosco)<br /><br />vão dizendo coisas, se concordam ou não com as propostas, se têm outras propostas, o que vos apetecer.<br /><br />beijitoschica de moebiushttps://www.blogger.com/profile/09496910420914050534noreply@blogger.comtag:blogger.com,1999:blog-11438609.post-62143988448624501792014-12-02T14:25:27.936+00:002014-12-02T14:25:27.936+00:00claro que sim.
até já...claro que sim.<br />até já...parreirexhttps://www.blogger.com/profile/03340253214797908391noreply@blogger.com